I can't understand scheme define, lambda, let clearly -


recently started learning scheme language

but don't know how solve problem.

(define   (lambda()     (let* ((x 2)            (c (lambda (p)                 (let ((x 4))                   (p))))            (d (lambda ()                 x))            (b (lambda ()                 (let ((x 3))                   (c d)))))       b)))

q. printed? how shallow binding , deep binding?

i briefly understand define, lambda, let* have no idea solve problem. how can solve it? please comment detailed explanation

the procedure returns procedure b. so

(a)

returns

#<procedure:b>

if want executed, have run

((a))

which whill call b , return

2

so happening? calling b call c d parameter. c therefore call d (bound parameter p). d returns x printed whatever value bound x in procedure d. since scheme lexically scoped, , d not have binding x, binding of lexical context used, comes from

(let* ((x 2)

which why 2 gets printed, regardless of other bindings d may exist in other procedures.


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