Babylonian Algorithm with C++ unable to get loop to run -


is refusal program produce result consequence of unable loop?

please find below code more information.

#include <iostream> #include <cmath> #include <iomanip>  using namespace std;  int main() {     double x, squareroot, oldsquareroot, counter=0;     cout << "enter positive number: " ;     cin >> x ;     {         (oldsquareroot = x/2; abs(squareroot-oldsquareroot) >= 1e-9 &&   abs(squareroot - oldsquareroot)>=(1e-8*x);counter++ )         {              squareroot = (squareroot+x/squareroot)/2;         }      }     cout << setprecision(15);     cout << "the value of squareroot is:" << squareroot << endl;     cout << "the number of interations required computation is:" <<  counter << endl;     return 0;   }

there mistakes. works fine.

#include <iostream> #include <cmath> #include <iomanip>  using namespace std;  int main() {     double x, squareroot, oldsquareroot, counter = 0;     cout << "enter positive number: ";     cin >> x;     {         squareroot = x; // fixed error 1: using of uninitialized variable.         (oldsquareroot = x / 2; abs(squareroot - oldsquareroot) >=  1e-9 && abs(squareroot - oldsquareroot) >= (1e-8*x); counter++)         {             oldsquareroot = squareroot;// fixed eror 2: oldsquareroot not changed in loop , can't exit.             squareroot = (squareroot + x / squareroot) / 2;         }     }     cout << setprecision(15);     cout << "the value of squareroot is:" << squareroot << endl;     cout << "the number of interations required computation is:" << counter << endl;     return 0; }

i hope you.


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