what does "unqualified on right hand side" mean in OOPs (Python)? -


i came across "unqualified on right hand side" phrase while reading oops concept in python usage self._customer = customer. phrase trying explain? complete statement is

for example, command, self._customer = customer, assigns instance variable self._customer parameter customer; note because customer unqualified on right-hand side, refers parameter in local namespace. --data structures , algorithms in python p. 72

according python docs

qualified name

a dotted name showing “path” module’s global scope class, function or method defined in module, defined in pep 3155. top-level functions , classes, qualified name same object’s name:

...

when used refer modules, qualified name means entire dotted path module, including parent packages, e.g. email.mime.text:

put more simply, qualifying name in python means explicitly define scope. self._customer qualified name (it identifies instance variable customer enclosing class) whereas bare customerreference not specify scope qualifications.

when name unqualified, python applies lexical scoping rules try , find variable, searching (in order)

  • local variables (including function parameters)
  • variables local outer functions, if we're dealing nested function definition
  • global variables
  • built-in variables

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