javascript - Why does using parseInt on Error return 14? -


consider following:

parseint(new array(), 10); // -> nan parseint(new array(), 16); // -> nan  parseint(new error(), 10); // -> nan parseint(new error(), 16); // -> 14

it seems behavior unique error/instances of error. can provide insight?

basically, that's because:

  • new error().tostring() yields "error", and
  • parseint("error", 16) yields 14 (because 0xe 14 , parser stops @ r).

on other hand, new array() not trigger same behavior because tostring() method of array objects returns contents of array, delimited commas, not class name. therefore, new array().tostring() yields empty string, , parseint() subsequently yields nan.


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