bash - To find latest entry for a particular record in the unix file -


i have file has multiple entries single record. example:

abc~20160120~120 abc~20160125~150 xyz~20160201~100 abc~20160205~200 xyz~20160202~90 pqr~20160102~250

the first column record name, second column date , third column entry particular date.

now want display in file latest entry particular record. how output should like

abc~20160205~200 xyz~20160202~90 pqr~20160102~250

can shell script same? keeping in mind have many records needs sorted first according record name , taking out latest 1 each record according date.

sort lines record name , date reversed, use -u unique flag of sort output first entry each record:

sort -t~ -k1,2r  < input-file | sort -t~ -k1,1 -u

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