How to convert 2002-05-30T09:30:10-06:00 to Unix time stamp using xslt 2.0 -


this logic trying use .should sub string 2002-05-30t09:30:10-06:00 , 2002-05-30t09:30:10 , 06:00 separate , subtract , use in below logic.if there easier way kindly let me know. {code}

<tns:timestamp>       <xsl:variable name="date" select="/order/@orderdate"/>        <xsl:value-of select='xs:datetime("1970-01-01t00:00:00") + @date *xs:daytimeduration("pt0.001s")'/>       </tns:timestamp>

i don't think should subtract offset in calculation. if do:

(xs:datetime(@orderdate) - xs:datetime('1970-01-01t00:00:00z')) div xs:daytimeduration('pt1s')

the result be:

1022772610

if convert unix time human readable time correct gmt , local time:

enter image description here

here's example (see working here)...

xml input

<order orderdate="2002-05-30t09:30:10-06:00"/>

xslt 2.0

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform"    xmlns:xs="http://www.w3.org/2001/xmlschema"   exclude-result-prefixes="xs">   <xsl:output indent="yes"/>    <xsl:template match="/order">     <order unix-time="{(xs:datetime(@orderdate) - xs:datetime('1970-01-01t00:00:00z'))        div xs:daytimeduration('pt1s')}">       <xsl:copy-of select="@*|node()"/>     </order>   </xsl:template>  </xsl:stylesheet>

xml output

<order unix-time="1022772610" orderdate="2002-05-30t09:30:10-06:00"/>

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