Elif error occured while the python programming - 


# input values. b1 = input('please enter base.') i1 = input('please enter index.')  # define funciton parameter 'base' , 'index'. def square(base, index):     if base == 0:         print('can\'t calculate because base equal 0.')     elif (not base == 0) , index == 0:         print('the value 0, because base greater 1, , index equal 0.')     elif (not base == 0) , index == 1:         print('the answer equal base, because index equal 1. therefore, answer {ans}.'.format(ans=base))     elif (not base == 0) , index == 2:         print('{b} squared {c}.'.format(b=base, c=(b ** 2))     elif (not base == 0) , (index > 2 or index < 0):         print('{b} power of {i} equal {c}'.format(b=base, i=index, c=base**index))  # print function. print(square(b1, i1))

the error this:

line 36, elif (not base == 0) , (index > 2 or index < 0):

syntaxerror: invalid syntax

i use python 3.5.1. how can fix error?

the problem not on line, on line above. did not close enough parentheses. try adding close parenthesis end of previous line.


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