ruby - Verify there is at least one table row on the page containing an arbitrary number of strings -


easier explained pseudocode in opinion:

page.all('tr').each |tr|     if tr.has_text?(string1) , tr.has_text?(string2) # , on...         # pass test!     end end # else fail test

does there exist effective way perform test using capybara , ruby/cucumber?

the following should you're trying do

strings = [string1, string2, ...] found = page.all('tr').any? |tr|   strings.all? { |s| tr.has_text?(s, wait: 0) } end expect(found).to true

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