ms access - I need a formula that finds a departure date between two given dates where the departure occurs later than a given time -


im using access 365 2016.

i need formula finds departure date between 2 given dates departure occurs later given time.

i have tried formula doesnt work:

between [date1] , [date2] (timevalue([date1] > 09:30

thank you

the formula quoted above simpler way of writing formula references controls on form.

the formula below references controls in flights form , exact formula used in expression builder. 

between [forms]![flights]![cbodeparture]      ,      [forms]![flights]![cbodeparture2]      ,      timevalue([forms]![flights]![cbodeparture])>[forms]![flights]![cbogreaterthantime])

i altered formula according code provided gustav in comments section neither code worked. see comments. code used method 1:

    (between [forms]![flights]![cbodeparture]  , [forms]![flights]![cbodeparture2])  , (timevalue([forms]![flights]![cbodeparture])>[forms]![flights]![cbogreaterthanti‌​me])

this code used method 2:

    between (datevalue([forms]![flights]![cbodeparture])+#09:30:00#)  , [forms]![flights]![cbodeparture2]

try with:

(between [date1] , [date2]) , (timevalue([date1]) > #09:30#)

or:

between (datevalue([date1]) + #09:30#) , [date2]

with comboboxes perhaps:

between datevalue([forms]![flights]![cbodeparture]) , datevalue([forms]![flights]![cbodeparture2]) , timevalue([forms]![flights]![cbodeparture]) > timevalue([forms]![flights]![cbogreaterthantime])

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