bash - AWK, can't match regex -

i learnig awk, , trying match word file contain @ leas 2 vowels. code is

#!/usr/bin/awk -f begin{c=0} {   for(i=1; i<=nf; i++){         if( match($i,"(.*[aeiou].*){2,}") > 0 )             c++     } } end{print c}

i using, test file, random stuff, like

asd e ef eseg <seg s<gko< <sg<se  eg eg eg  peaorj<ÈmofepriagÒajpd<skakropdsaf foeipsfipiè<+oèipiau aeiouaeiou

i tested regex on myregextester.com , there seems work. mistaking?

your awk script can refactored (or simplified) (gnu-awk):

awk -v rs='[[:space:]]+' '/(.*[aeiouaeiou].*){2}/{c++} end{print c+0}' file

it output:

because count words vowels have included upper case vowels character class.

-v rs='[[:space:]]+' split input records of single word.

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