C: adding elements to an array -

i'm trying test program creates array 0 elements in it, adds elements (reallocating memory each time), , printing out elements. but, keep getting errors when try run it.

int main(int argc, const char * argv[]) {     int num = 0;     int n = 10;     int **array = malloc(0);     (int = 0; < n; ++i)     {         ++num;         array = realloc(array, num * sizeof(int*));         array[num-1] = &i;       }     (int j = 0; j < n; ++j)     {         printf("%d", &array[j]); // error 1     }     return 0; } 

i'm sorry didn't include errors original post. think fixed 1 of them. here other:

error 1: format specifies type 'int' argument has type 'int *'

this answer based on assumption printing simple array, since don't show output expect. using 1 more step of indirection need, , many variables. take note indexing different length (often 1).

#include <stdio.h> #include <stdlib.h>  int main(void) {     int i, n = 10;     int *array = null;                  // no need double star, or fake allocation     (i = 0; < n; ++i)     {         array = realloc(array, (i + 1) * sizeof(int));  // remove *, add 1 num elements         array[i] = i;     }     (i = 0; < n; ++i)     {         printf("%d", array[i]);                 // remove &     }      free(array);                                // don't forget     return 0; } 

program output:

0123456789 

in practice, should assign result of realloc pointer variable, check it's ok, , replace original pointer var.