mysql - Every Derived Table must have it's own alias -


here mysql syntax:

select f1.id   (select f1.id,           count(*) c1    (friend f1          join friend f2 on (f1.fid=f2.fid                                , f1.id!=f2.id                                , f2.id=12345                                , f1.id!=12345))) c1>=     (select count(*)      friend f3      f3.id=12345);

i can't seem figure out where's problem, tried aliasing inner result tables seem return error! need guidelines.

get rid of extraneous parenthesis , format query bit have cleaner look:

select t.id  (select f1.id,count(*) c1        friend f1        join friend f2          on  f1.fid=f2.fid ,               f1.id!=f2.id ,               f2.id=12345 ,               f1.id!=12345) t -- <-- alias needed here! c1>=(select count(*) friend f3 f3.id=12345)

if format above, you'll realize derived table of query missing alias.

also, field selected outermost query, i.e. id should prefixed using alias of derived table, i.e. t.


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