Get sizeof a void (*)() function pointer in C -


to aid precise memory allocation i'm doing in c, i'm trying sizeof function pointer function return type void takes no parameters.

however, when sizeof (void (*)()), generate compiler warning:

function declaration isn’t prototype [-wstrict-prototypes]

how size i'm looking for?

that old style function definition, missing argument list, add them:

sizeof( void(*)(void) )

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