bash - How to get second value of second column in output -


i have output this:

name              cluster_ip     external_ip   port(s)    selector                  age docker-registry   172.30.131.5   <none>        5000/tcp   docker-registry=default   33m

now want ip. nothing else. used awk got cluster_ip too

result=$(oc svc/docker-registry | awk '{print $2}')

just select 2nd line:

result=$(oc svc/docker-registry | awk 'nr==2{print $2}')

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