java - how comparable interface return int value, if an interface having only method declaration - 


string s1="aaa"; string s2="bbb"; int result_int = s1.compareto(s2);

the result_int -ve value, means .compareto method says s1 lesser s2. question is=> if .compareto method comparable interface,then interface method how should have body?? if compareto method doesn't have body, how return integer value while passing 2 objects.

compareto method have implementation. method implemented in classes such integer, double etc. in case using string's compareto method.

if want customized per class, overriding compareto method.


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