Inclusive date ranges in python -

i didn't phrase question correctly , result, none of answers quite hit mark.

what wanted know is, what's best way time return end of day in epoch milliseconds, if given date, rather both date , time?

here's how i'm doing @ moment:

def get_epoch_endofday(day):     return time.mktime(time.strptime('005923'+day,"%s%m%h%d%m%y"))*1000 

the function takes date in form ddmmyy, , spits out epoch milliseconds on day @ 23:59:00.

i wondered, there more elegant way of doing this?

it wasn't clear @ first, want create interval given day (say 2016-02-14), contains first , last instant of day. means:

first instant: 2016-02-14 00:00:00.000

last instant: 2016-02-14 23:59:59.999

the function below returns interval tupel. works this:

• create start of interval creating new date instance on same day hours, minutes , milliseconds set 0
• create interval spanning 23 hours, 59 minutes, 59 seconds , 999999 microseconds
• add interval beginning of day

code:

from datetime import datetime, timedelta  # 2016-02-08 11:39:31.093209 day = datetime.now()  def get_day_interval(day):     start = datetime(day.year, day.month, day.day)     interval = timedelta(seconds=59, microseconds=999999, minutes=59, hours=23)     return (start, start + interval)  (start, end) = get_day_interval(day)  # 2016-02-08 00:00:00 print(start)  # 2016-02-08 23:59:59.999999 print(end) 

consult python docs more options.

if interval can exclusive, code becomes simpler, see summary of this answer.