math - Proof big omega of 1^k+2^k+..+n^k -
question:
1^k + 2^k + ... + n^k big omega of n^(k+1) 1^k + 2^k + ... + n^k => cn^(k+1)
hi, need figure out how can prove this. trying avoid induction , proving simple possible.
use integrals. sum larger the
integral of x^k 0 n
and smaller
integral of x^k 1 n+1.
thus theta class. , c=1/(k+1).
Comments
Post a Comment