How do i output sum of rows of a 2D array C++ -


edit: i'm new c++. began working language 2 weeks ago.

sorry if have been asked before, have searched everywhere on web on how sum individual rows in 2d array , not found answer looking for.

i need display sum of each individual row in a[m][n], reason works when array 2x2, if it's 3x3 or bigger, following output in terminal:

for intsance, a[3][3]=  {1,2,3},   //this determined user {1,2,3}, {1,2,3};  following output: 9179942 //address of sort??? 6       // actual sum. code working here (yay :d) 469090925// again dont understand

this have far

#include <iostream> using namespace std; int main(){ int m,n; cout<<"enter number of rows array"<<endl; cin>>m; if (m>10){     cout<<"more 10 rows big"<<endl;     return 1;    }  cout<<"enter number of collumns array"<<endl; cin>>n; if (n>10){     cout<<"more 10 collumns big"<<endl;     return 1; }  int a[m][n]; for(int i=0; i<m;i++){     cout<<"enter "<<m<<" values row "<<i+1<<endl;     for(int j=0; j<n; j++){         cout<<"a ["<<i<<"]["<<j<<"]: ";         cin>>a[i][j];     } } cout<<"array dimensions: "<<m<<"x"<<n<<'\n'<<"resulting array: "<<endl; for(int i=0; i<m;i++){     for(int j=0; j<n; j++){         cout<<a[i][j]<<"    ";     }     cout<<endl; } int avg[m]; int el_less_avg; for(int i=0; i<m; i++){     for(int j=0; j<n;j++){         avg[i]+=a[i][j];     } }cout<<"\n\n"; for(int i=0; i<m; i++){      cout<<avg[i]<<endl; }  return 0; } 

int avg[m]; int el_less_avg; for(int i=0; i<m; i++){     for(int j=0; j<n;j++){

you're not initializing these values they're free whatever cruft on stack @ time. need initialize them.

int avg[m]; (int = 0; < m; ++i) {     avg[i] = 0;     (int j = 0; j < n; ++j) {         avg[i] += a[i][j];     } }

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