How to transform a XML using XSLT only modifying a node that's required? -


i'm trying transform xml replace node name another, xslt framed messing transformed xml. might small issue might have overlooked, stuck long time.

input xml have:

<?xml version="1.0" encoding="utf-8"?> <datacollection>     <queryconst language="dbsql">         <queryused>             select emp.firstname, emp.lastname (select firstname, lastname             employees employeeid &lt; 10) emp         </queryused>     </queryconst>     <record>         <old>             <employees>                 <firstname>james</firstname>                 <lastname>gosling</lastname>             </employees>         </old>     </record>     <record>         <old>             <employees>                 <firstname>rod</firstname>                 <lastname>johnson</lastname>             </employees>         </old>     </record> </datacollection>

the xslt used follows:

<xsl:stylesheet version="1.0"     xmlns:xsl="http://www.w3.org/1999/xsl/transform">     <xsl:output method="xml" omit-xml-declaration="yes" indent="yes" />     <xsl:template match="node()|@*">         <xsl:copy>             <xsl:apply-templates select="node()|@*" />         </xsl:copy>     </xsl:template>     <xsl:template match="datacollection/queryconst/@language">         <xsl:attribute name="language">dbview</xsl:attribute>     </xsl:template>     <xsl:template match="datacollection/record/old/employees">         <xsl:element name="table">             <xsl:copy>                 <xsl:apply-templates select="node()|@*" />             </xsl:copy>         </xsl:element>     </xsl:template> </xsl:stylesheet>

the output xml want follows:

<?xml version="1.0" encoding="utf-8"?> <datacollection>     <queryconst language="dbview">         <queryused>             select emp.firstname, emp.lastname (select firstname,             lastname employees employeeid &lt; 10) emp         </queryused>     </queryconst>     <record>         <old>             <table>                 <firstname>james</firstname>                 <lastname>gosling</lastname>             </table>         </old>     </record>     <record>         <old>             <table>                 <firstname>rod</firstname>                 <lastname>johnson</lastname>             </table>         </old>     </record> </datacollection>

any / tips / suggestions on above appreciated.

you need remove xsl:copy template matching employees. also, there's no need use xsl:element when element name known. try simply:

<xsl:template match="datacollection/record/old/employees">     <table>         <xsl:apply-templates/>     </table> </xsl:template>

note match pattern not select expression. don't need use path unless have other employees nodes elsewhere in input xml. given example, 

<xsl:template match="employees">

would quite sufficient.


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